28n^2-64n+36=0

Solution for 28n^2-64n+36=0 equation:

28n^2-64n+36=0

a = 28; b = -64; c = +36;
Δ = b2-4ac
Δ = -642-4·28·36
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8}{2*28}=\frac{56}{56}
=1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8}{2*28}=\frac{72}{56}
=1+2/7
$